I mean “because password hashes” is basically my original rational so not sure it qualifies as a counter argument.
But the link you provide is more explicit:
> When the user enters the new password, the system generates the variations of the new password entered, hashes each one of them, and compares each hash against the old password’s hash. If any of the hash matches, it throws an error. Else, it successfully changes the password
It is possible to hash all 1 character variations I guess, I kinda doubt that it is done often (does anyone know a library?).
I guess complexity increases linearly so password length is might not severely limit this mechanism.
It would be interesting to see a calculation of how long it takes for a long password can to calculate all possibilities for 1 char variations for utf-8 or other charsets
No, because password hashes. Read this: https://security.stackexchange.com/questions/139738/company-can-tell-if-new-and-old-passwords-are-too-similar-is-there-a-security-p
I mean “because password hashes” is basically my original rational so not sure it qualifies as a counter argument.
But the link you provide is more explicit:
> When the user enters the new password, the system generates the variations of the new password entered, hashes each one of them, and compares each hash against the old password’s hash. If any of the hash matches, it throws an error. Else, it successfully changes the password
It is possible to hash all 1 character variations I guess, I kinda doubt that it is done often (does anyone know a library?).
I guess complexity increases linearly so password length is might not severely limit this mechanism. It would be interesting to see a calculation of how long it takes for a long password can to calculate all possibilities for 1 char variations for utf-8 or other charsets
Thanks for sharing the link!
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